Answer:
The distance between the ball in the room is
![4.2\ in](https://img.qammunity.org/2020/formulas/mathematics/high-school/j6i7yg5hgmtql761nyu5p7a8zt22i7qa5d.png)
Explanation:
We know that for a circumference the radius is equal to half the diameter.
![r =(d)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/nfxcihairy4747521y93tw4177ud5d6xir.png)
The diameter of the basketball hoop is 18 inches.
Then the radius of the hoop is:
![r = (18)/(2)\\\\r = 9\ inches](https://img.qammunity.org/2020/formulas/mathematics/high-school/cvlwh9z5t3rdxob34wssgzoudy1fz6gatg.png)
If, the circumference of the ball is 30 inches then the circumference C is:
![C = 2(\pi)r=30](https://img.qammunity.org/2020/formulas/mathematics/high-school/3ipgl2tk0idrxu8g4rbo9v6re8dz17ztlu.png)
And the radius of the ball is:
![30 = 2(\pi)r\\\\r =(15)/(\pi)](https://img.qammunity.org/2020/formulas/mathematics/high-school/exd3p65p4sbpjxmiu80nvjwpb11mm3p6xl.png)
So the distance between the ball and the ring will be equal to the difference of both radius.
![k = 9-(15)/(\pi)\\\\k = 4.2\ in](https://img.qammunity.org/2020/formulas/mathematics/high-school/s4qadd1v234w5g2st2svf98ectjtziei5h.png)