Answer:
The correct option is 2.
Explanation:
The given matrix multiplication is
![\begin{bmatrix}2&4&-3\\ 6&1&0\end{bmatrix}* \begin{bmatrix}-3&2\\ -2&3\\ -8&5\end{bmatrix}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7tpsmmu4ags04ol6c1buwdgiye0isxxy7e.png)
Order of matrix = Number of rows × Number of columns
Let
![A=\begin{bmatrix}2&4&-3\\ 6&1&0\end{bmatrix},B=\begin{bmatrix}-3&2\\ -2&3\\ -8&5\end{bmatrix}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/u5aczvba6feoj77mlx6psb5373rhi590s1.png)
Order of matrix A = 2 × 3
Order of matrix B = 3 × 2
The order of product of two matrices is
![A_(m* n)\cdot B_(n* k)=AB_(m* k)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wz3a1qw6qu66wwjyc4l8u7lhn1n8f1ekl4.png)
It means
Order of product = Number of rows of first matrix × Number of columns of second matrix
Order of product = 2 × 2
![A_(2* 3)\cdot B_(3* 2)=AB_(2* 2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fox6qbcxt84v2gebj2z9vxd9qi0jydg6ks.png)
The dimensions of the product are 2 × 2. Therefore the correct option is 2.