Answer:
The correct option is 2.
Explanation:
The given matrix multiplication is

Order of matrix = Number of rows × Number of columns
Let

Order of matrix A = 2 × 3
Order of matrix B = 3 × 2
The order of product of two matrices is

It means
Order of product = Number of rows of first matrix × Number of columns of second matrix
Order of product = 2 × 2

The dimensions of the product are 2 × 2. Therefore the correct option is 2.