85.9k views
4 votes
y=2x^2/3x^2-16 what is the horizontal asymptote for the above function? round to the nearest thousandth.

User Djsmith
by
5.9k points

1 Answer

4 votes

Answer:

0.667

Explanation:

Performing the indicated division gets you ...

y = (2/3) + (32/3)/(3x^2 -16)

The term containing x goes to zero as x gets large, leaving y = 2/3 as the horizontal asymptote. In decimal form, this is approximately ...

y = 0.667

User Siddharth Nayar
by
5.4k points