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Solve the inequality:

8 - 2x <4

A. X> -2. B. X>2. C. X<2. D. X>6

|x-8| >22

A. X> -30 or x< -14
B. X> 30 or x< 14
C. X> 30 or x < 14
D. X> 30 and x < 14

|x+5| < 4

A. -9 B. -5 < x <4
C. -1 < x <4
D. -1 < x <9

User Dsgdfg
by
5.8k points

1 Answer

3 votes

Answer:

8 - 2x <4 gives us x>2

|x-8| >22 gives us (-inf, -14) and (30,inf)

|x+5| < 4 gives us (-9,-1)

Explanation:

Inequalities differs from equalities in that they return a range of values for x and not a single value (case of equalities)

The first one

8 - 2x <4 if you subtract every side 8, you will get -2x<-4

Next divide every side with -2, since its a negative number you have to change the orientation of the inequaiity, thus we have x>4/2, x>2

The second

|x-8| >22, it has to be treated as this. -22>x-2>22 which can be treated as two single inequalities, -22>x-8, and the other, x-8>22. The fist gives you x<-14, and the other x>30, two non intercepting ranges, so your range will be (-inf, -14) and (30, inf)

The third

|x+5| < 4 if you apply the same steps from above, you will have the following -4<x+5<4 This results in two intercepting ranges, giving you the range (-9,-1)

User Whp
by
4.7k points
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