Answer:
The answer is actually 1.76x10^-11
Step-by-step explanation:
Fill in the box 1.76 and then -11
1.758 x 10⁻¹¹.
∵ pH = - log[H⁺].
∴ 5.47 = -log[H⁺].
log[H⁺] = -5.47.
∴ [H⁺] = 3.388 x 10⁻⁶ M.
∵ [H⁺] = √(Ka.C)
∴ [H⁺]² = Ka.C
∴ Ka = [H⁺]²/C = (3.388 x 10⁻⁶)²(0.653) = 1.758 x 10⁻¹¹.
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