Question

In circle K , diameter CD is drawn and point E is located on the circle such that CE=16 and DE=30 .What is the length of the radius of circle K?

Answer 1

The length of the radius of the circle K is
`17\ units`

Explanation:

we know that

The triangle CDE is a right triangle with the 90 degree angle at point E

so

Applying the Pythagoras Theorem

Find the length of CD (diameter of the circle K)

`CD^(2)=CE^(2)+DE^(2)`

substitute the values

`CD^(2)=16^(2)+30^(2)`

`CD^(2)=1,156`

`CD=34\ units`

Find the radius

Remember that the radius is half the diameter

so

`r=34/2=17\ units`