Question

Factor problems 9 - 12 by using the difference of squares method.

9. x2 – 4
A. This polynomial cannot be factored by using the difference of squares method.
B. (x – 2)(x – 2)
C. (x – 2)(x – 1)
D. (x – 2)(x + 2)
E. (x – 1)(x – 4)
F. (x + 2)(x + 2)
10. x2 – 25
A. (-x – 5)(x - 5)
B. This polynomial cannot be factored by using the difference of squares method.
C. (-x + 5)(x + 5)
D. (x – 5)(x + 5)
E. (x + 5)(-x - 5)
F. (x – 5)(x - 5)
11. 36x4 – 4x2
A. (6x2 – 2x)(6x2 - 2x) = 4x2(3x - 1)(3x - 1)
B. (6x2 + 2x)(6x2 + 2x) = 2x2(3x + 1)(2x + 1)
C. This polynomial cannot be factored by using the difference of squares method.
D. (-6x2 – 2x)(-6x2 - 2x) = 4x2(-3x - 1)(-3x - 1)
E. (6x2 – 2x)(6x2 + 2x) = 4x2(3x - 1)(3x + 1)
F. (-6x2 + 2x)(6x2 - 2x) = 2x2(-3x + 1)(3x - 1)
12. x2 + 100
A. (x + 10)(x – 10)
B. (-x + 10)(x – 10)
C. (x + 10)(x + 10)
D. This polynomial cannot be factored by using the difference of squares method.
E. (x - 10)(x – 10)
F. (-x + 10)(-x – 10)

Answer 1

Explanation:

9. D

10.D

11.E

12.D

Answer 2

9.

`x^2-4\\(x-2)(x+2)`

10.

`x^2-25\\(x-5)(x+5)`

11.

`36x^4-4x^2\\4x^2(9x^2-1)\\4x^2(3x+1)(3x-1)`

12.

`x^2+100\\`

This polynomial cannot be factored by using the difference of squares method