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How do you do this problem?

How do you do this problem?-example-1

2 Answers

3 votes
X=-.5, it’s less than 0, and concave up & increasing in this situation are the same.
User Stas Boyarincev
by
8.7k points
7 votes

Answer:

x = -0.5

Explanation:

I have marked on the graph the values of ƒ(x) that correspond to the different x-values.

At x = -2.5, ƒ(x) is decreasing, concave up, and > 0.

At x = -1.5, ƒ(x) is decreasing, concave down, and < 0.

At x = -0.5, ƒ(x) is increasing, concave up, and < 0.

At x = 0.5, ƒ(x) is increasing, concave up, and > 0.

At x = 2.5, ƒ(x) is decreasing, concave up, and > 0.

The only point for which ƒ(x) is simultaneously increasing, concave up, and less than zero is x = -0.5.

How do you do this problem?-example-1
User Dmerlea
by
8.5k points

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