Question

How do you do this problem?

Answer 1

X=-.5, it’s less than 0, and concave up & increasing in this situation are the same.

Answer 2

x = -0.5

Explanation:

I have marked on the graph the values of ƒ(x) that correspond to the different x-values.

At x = -2.5, ƒ(x) is decreasing, concave up, and > 0.

At x = -1.5, ƒ(x) is decreasing, concave down, and < 0.

At x = -0.5, ƒ(x) is increasing, concave up, and < 0.

At x = 0.5, ƒ(x) is increasing, concave up, and > 0.

At x = 2.5, ƒ(x) is decreasing, concave up, and > 0.

The only point for which ƒ(x) is simultaneously increasing, concave up, and less than zero is x = -0.5.