Question

W^2-7over3w+49over36=0 solve the equation​

Answer 1

`\large\boxed{w=(7)/(6)}`

Explanation:

`w^2-(7)/(3)w+(49)/(36)=0\qquad\text{multiply both sides by 36}\\\\36w^2-36\!\!\!\!\diagup^(12)\cdot(7)/(3\!\!\!\!\diagup_1)w+36\!\!\!\!\diagup^1\cdot(49)/(36\!\!\!\!\diagup_1)=0\\\\36w^2-84w+49=0\\\\36w^2-42w-42w+49=0\\\\6w(6w-7)-7(6w-7)=0\\\\(6w-7)(6w-7)=0\\\\(6w-7)^2=0\iff 6w-7=0\qquad\text{add 7 to both sides}\\\\6w=7\qquad\text{divide both sides by 6}\\\\\boxed{w=(7)/(6)}`

Answer 2

7/6

Explanation:

w^2 - 7/3 w + 49/36 = 0

It's perfect square

(w - 7/6)^2 = 0

w - 7/6 = 0

w = 7/6