Question

Plz, help!!!!! Solve the given system, using the substitution method.

y = 4x – 6

8x – 2y = 14




(14, 12)


(12, 14)


There is an infinite number of solutions.


There is no solution.

Answer 1

`\large\boxed{There\ is\ no\ solution}`

Explanation:

`\left\{\begin{array}{ccc}y=4x-6&(1)\\8x-2y=14&(2)\end{array}\right\\\\\text{Put (1) to (2):}\\\\8x-2(4x-6)=14\qquad\text{use the distributive property}\\\\8x+(-2)(4x)+(-2)(-6)=14\\\\8x-8x+12=14\\\\12=14\qquad\bold{FALSE}\\\\Conclusion:\\\\\text{There is no solution.}`

Answer 2

There is no solution.

Explanation:

`\begin{bmatrix}y=4x-6\\ 8x-2y=14\end{bmatrix}`

Plug in the y value.

`8x-2\left(4x-6\right)=14`

`-2=0`

Since that equation is false, then the system has no solution.