110k views
3 votes
The quadratic model f(x)=-5x^2 +200 represents the approximate height, in meters, of a ball x seconds after being dropped. The ball is 50 meters from the ground after about how many seconds

2.45
3.16
5.48
7.07

2 Answers

7 votes

Answer:

5.48

Explanation:

User Artplastika
by
8.6k points
3 votes

Answer:

Third option: 5.48

Explanation:

Given the quadratic model that represents the approximate height in meters of the ball
f(x)=-5x^2 +200. the time in seconds x, when the ball is 50 meters from the ground can be calculated by substituting
f(x)=50 and solving for x.

Then:


50=-5x^2 +200

Subtract 200 from both sides:


-200+50=-5x^2 +200-200\\-150=-5x^2

Divide both sides by -5:


(-150)/(-5)=(-5x^2)/(-5)\\30=x^2

Apply square root to both sides:


√(30)=√(x^2)\\√(30)=x\\5.48=x

The ball is 50 meters from the ground after about 5.48 seconds.

User Albi
by
7.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.