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3 votes
The quadratic model f(x)=-5x^2 +200 represents the approximate height, in meters, of a ball x seconds after being dropped. The ball is 50 meters from the ground after about how many seconds

2.45
3.16
5.48
7.07

2 Answers

7 votes

Answer:

5.48

Explanation:

User Artplastika
by
7.6k points
3 votes

Answer:

Third option: 5.48

Explanation:

Given the quadratic model that represents the approximate height in meters of the ball
f(x)=-5x^2 +200. the time in seconds x, when the ball is 50 meters from the ground can be calculated by substituting
f(x)=50 and solving for x.

Then:


50=-5x^2 +200

Subtract 200 from both sides:


-200+50=-5x^2 +200-200\\-150=-5x^2

Divide both sides by -5:


(-150)/(-5)=(-5x^2)/(-5)\\30=x^2

Apply square root to both sides:


√(30)=√(x^2)\\√(30)=x\\5.48=x

The ball is 50 meters from the ground after about 5.48 seconds.

User Albi
by
6.7k points