What are the solutions to the inequality (x-3)(x+5) greater than or equal to 0?

Question

asked Dec 1, 2020 48.1k views

2 Answers

Tiago Leite · Answer 1 · 2020-12-03T07:29:48+0000

Answer:

C

Explanation:

If this was an equation...

(x-3)(x+5) = 0

x = 3, -5

So 3 and -5 are the minimum and the maximums.

So we convert that into an inequality.

-5 <= x <= 3

NishM · Answer 2 · 2020-12-07T11:06:56+0000

For this case we must find the solutions of the following inequality:

$(x-3)(x+5)\leq0$

For
(x-3)(x+5)=0 we have the following solutions:

$x=3\\x=-5$

As a possible solution we have the following intervals:

$x\leq -5\\-5\leq x\leq 3\\x\geq 3$

We must choose a value included in each of the possible intervals, replace them in the original inequality and verify if it is fulfilled.

$(-6-3)(-6+5)\leq 0\\-9*-1\leq0\\ 9\leq0$

It is not true

$(0-3)(0+5)\leq 0\\-3*5\leq 0\\-15\leq0$

It is true.

ANswer:

Option C