Answer:
The volume of the container is
![38,772.72\ cm^(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/30mhoh3jyaf8300vm51vdibnpau8jpaj80.png)
Explanation:
step 1
Find the radius of the sphere
we know that
The surface area of a sphere is equal to
![SA=4\pi r^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lrtreitqwe2s2tkkhr0xyobeh0wqs4gs7k.png)
we have
![SA=5,538.96\ cm^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xldgt3dqis7ysce65e64b0xb0830a8y4gq.png)
![\pi=3.14](https://img.qammunity.org/2020/formulas/mathematics/middle-school/elnllul6m5wik5ibdc7x3b8auxqsmgjtbn.png)
substitute the values and solve for r
![5,538.96=4(3.14)r^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/y9hrcs8frxqawgb6mev3qql5pt0gkscchi.png)
![r^(2)=5,538.96/[4(3.14)]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mfdtzz078e5qznotysb63myv75h9scrhgm.png)
![r^(2)=441](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8m8nbmwfai0ftiobfr112vv6xxk1njsn7o.png)
![r=21\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3n6t8vtu7v11f8u1nq8874jpjqtu8w4xc8.png)
step 2
Find the volume of the container
The volume of the sphere (container) is equal to
![V=(4)/(3)\pi r^(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/904v6t92j764tuemw89ou00p3u81fhmqpa.png)
we have
![r=21\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3n6t8vtu7v11f8u1nq8874jpjqtu8w4xc8.png)
![\pi=3.14](https://img.qammunity.org/2020/formulas/mathematics/middle-school/elnllul6m5wik5ibdc7x3b8auxqsmgjtbn.png)
substitute the values
![V=(4)/(3)(3.14)(21)^(3)=38,772.72\ cm^(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3pj7wco5qgfvjkjnr6b1w0rpp2qv6gsr3o.png)