Answer:
Electric field, E = 5 N/C
Step-by-step explanation:
It is given that,
Charge on the point charge,
![Q=6\ \mu C=6* 10^(-6)\ C](https://img.qammunity.org/2020/formulas/physics/high-school/dh71g1s6tzteris793toql7hvxl3ox8inq.png)
Distance at which the point charge is placed, d = 100 m
Electric field is given by :
![E=(kQ)/(r^2)](https://img.qammunity.org/2020/formulas/physics/high-school/8e0k0i72udo88kpdmutn36uvp735854zrh.png)
![E=(9* 10^9* 6* 10^(-6))/((100)^2)](https://img.qammunity.org/2020/formulas/physics/high-school/zogi86oc1wwsbnmzfbrhzhe6t7sovd6ks4.png)
E = 5.4 N/C
E = 5.4 N/C
or E = 5 N/C
Hence, this is the required solution.