Question

A motorcycle of mass 100 kilograms slowly rolls off the edge of a cliff and falls for three seconds before reaching the bottom of a gully. Its momentum upon hitting the ground is

A) 1,000 kg m/s.
B) 2,000 kg m/s.
C) 3,000 kg m/s.
D) 4,000 kg m/s.
E) 9,000 kg m/s.

Answer 1

C) 3,000 kg m/s

Step-by-step explanation:

We can consider the horizontal velocity of the motorcycle to be zero, since it rolls off the edge of the cliff very slowly. So, we only need to find the vertical velocity at the time of the impact with the ground.

The vertical velocity of the motorcycle at time t is given by (free-fall motion):

`v(t)=v_0 -gt`

where

`v_0=0` is the initial vertical velocity (zero, since the motorcycle is not moving)

g = 9.8 m/s^2 is the acceleration due to gravity

t is the time

Since the motorcycle hits the ground after t = 3 seconds, we have

`v(3 s)=0-(9.8 m/s^2)(3 s)=-29.4 m/s`

And since we know its mass, m=100 kg, we can find its momentum:

`p=mv=(100 kg)(-29.4 m/s)=-2940 kg m/s \cdot -3000 kg m/s`

and the negative sign simply means downward direction.