Find the difference of the given polynomials (8x^2-3x+1/3)-(2x^2-8x+3/5)

Question

asked Apr 12, 2020 6.0k views

1 Answer

Sey · Answer 1 · 2020-04-19T03:08:42+0000

Answer:

$\boxed{\bold{6x^2+5x-(4)/(15)}}$

Step-by-step explanation:

[ Step One ] Remove Parenthesis: (a) = a

$\bold{8x^2-3x+(1)/(3)-\left(2x^2-8x+(3)/(5)\right)}$

[ Step Two ] Simplify:
$\bold{-\left(2x^2-8x+(3)/(5)\right): \ -2x^2+8x-(3)/(5)}$

$\bold{8x^2-3x+(1)/(3)-2x^2+8x-(3)/(5)}$

[ Step Three ] Simplify
$\bold{8x^2-3x+(1)/(3)-2x^2+8x-(3)/(5): \ 6x^2+5x+(1)/(3)-(3)/(5)}$

$\bold{6x^2+5x-(4)/(15)}$

[
$\boxed{\bold{Final \ Answer}}$ ]

➤
$\bold{6x^2+5x-(4)/(15)}$

$\boxed{\bold{Mordancy}}$