6.0k views
3 votes
Find the difference of the given polynomials (8x^2-3x+1/3)-(2x^2-8x+3/5)

1 Answer

1 vote

Answer:


\boxed{\bold{6x^2+5x-(4)/(15)}}

Step-by-step explanation:

[ Step One ] Remove Parenthesis: (a) = a


\bold{8x^2-3x+(1)/(3)-\left(2x^2-8x+(3)/(5)\right)}

[ Step Two ] Simplify:
\bold{-\left(2x^2-8x+(3)/(5)\right): \ -2x^2+8x-(3)/(5)}


\bold{8x^2-3x+(1)/(3)-2x^2+8x-(3)/(5)}

[ Step Three ] Simplify
\bold{8x^2-3x+(1)/(3)-2x^2+8x-(3)/(5): \ 6x^2+5x+(1)/(3)-(3)/(5)}


\bold{6x^2+5x-(4)/(15)}

[
\boxed{\bold{Final \ Answer}} ]


\bold{6x^2+5x-(4)/(15)}


\boxed{\bold{Mordancy}}

User Sey
by
4.8k points