Question

On a coordinate plane, what is the distance between the points (-4, -3) and (-1, 5)? Round your answer to the nearest hundredth.

Answer 1

The distance between the two points is 8.54 to the nearest hundredth.

EXPLANATION

We want to find the distance between the the points (-4, -3) and (-1, 5).

We use the distance formula;

`d=√((x_2-x_1)^2+(y_2-y_1)^2)`

`d=√(( - 1 - -4)^2+(5- - 3)^2)`

`d=√(( 3)^2+(8)^2)`

`d=√(9+64)`

`d = √(73)`

`d = 8.544`

To the nearest hundredth the distance is 8.54 units.

Answer 2

8.54

Explanation:

To find the distance between 2 points

d = sqrt( y2-y1)^2 + (x2-x1)^2)

where (x1,y1) and (x2,y2) are the two points

d = sqrt((5--3)^2+ (-1--4)^2)

= sqrt((5+3)^2+ (-1+4)^2)

= sqrt((8)^2+ (3)^2)

= sqrt(64+ 9)

=sqrt (73)

=8.544003745

Rounding to the nearest hundredth

=8.54