What is the length of segment EF? EF = square root of 58 end square root EF = three square root of 10 end square root EF = 9 EF = 90

Question

asked Oct 1, 2020 194k views

1 Answer

Invisiblerhino · Answer 1 · 2020-10-05T18:36:55+0000

Answer:

$EF=3√(10)\ units$ ------> three square root of 10

Explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}$

In this problem we have

$E(-1,-1)\\F(8,-4)$

substitute the values

$EF=\sqrt{(-4+1)^(2)+(8+1)^(2)}$

$EF=\sqrt{(-3)^(2)+(9)^(2)}$

$EF=√(90)\ units$

$EF=3√(10)\ units$