Question

What is the length of segment EF?

EF = square root of 58 end square root

EF = three square root of 10 end square root

EF = 9

EF = 90

Answer 1

`EF=3√(10)\ units` ------> three square root of 10

Explanation:

we know that

the formula to calculate the distance between two points is equal to

`d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}`

In this problem we have

`E(-1,-1)\\F(8,-4)`

substitute the values

`EF=\sqrt{(-4+1)^(2)+(8+1)^(2)}`

`EF=\sqrt{(-3)^(2)+(9)^(2)}`

`EF=√(90)\ units`

`EF=3√(10)\ units`