Question

What are the x intercepts of the equation function? Y=x^2+2x-1

Answer 1

(-1 + √2) and (-1 - √2)

Explanation:

Given in the question the equation

y = x² + 2x - 1

To find the x-intercept, substitute in 0 for y

0 = x² + 2x - 1

To find value of x use quadratic equation

x = -b ± √b²-4ac / 2a

here a = 1

b = 2

c = -1

x1 = -2 + √2²-4(1)(-1) / 2(1)

= -2 + 2√2 / 2

= -1 + √2

x2 = -2 - √2²-4(1)(-1) / 2(-1)

= -2 - 2√2 / -2

= -1 - √2