Question

A member of a book club wishes to purchase two books from a selection of eight books recommended for a certain month. In how many ways can she choose them?

Answer 1

28 was right on acellus

Explanation:

Answer 2

She can chose 2 books from 8 books in 28 different way.

Explanation:

In the given scenario the member has to chose 2 books from a group of 8 books. The order of choosing books does not matter. For example if the books are A,B,C,D,E,F,G and H, and the member picks books A and B or books B and A, she is picking up the same books. This means order of selection does not matter here, so this is a problem of combinations.

We have to form combination of 8 books taken 2 at a time i.e. 8C2

The general formula of combination is:

`nCr=(n!)/(r!(n-r)!)`

Using the values of n=8 and r=2, we get:

`8C2=(8!)/(2!(8-2)!)=28`

This means, she can chose 2 books from 8 books in 28 different ways.