Question

Use the x-intercept method to find all real solutions of the equation.
x^3-6x2+3x+10=0

Answer 1

Three solutions were found :

x = 5

x = 2

x = -1

Explanation:

Answer 2

d.
`x=-1,2,\:or\:5`

Explanation:

The given equation is;

`x^3-6x^2+3x+10=0`

To solve by the x-intercept method we need to graph the corresponding function using a graphing calculator.

The corresponding function is

`f(x)=x^3-6x^2+3x+10`

The solution to
`x^3-6x^2+3x+10=0` is where the graph touches the x-axis.

We can see from the graph that; the x-intercepts are;

(-1,0),(2,0) and (5,0).

Therefore the real solutions are:

`x=-1,2,\:or\:5`