Question

Let f(x)=6/−2+2e^−0.3x . What is f(−4) ?

DID THE TEST
ANSWER: 1.3

Answer 1

1.94

Explanation:

We substitute -4 into as x in the equation, but first what is e?

e is a term that represents the base of a natural logarithm and is a irrational number, its called Euler's number. e is equivalent to:

`e=2.718`

We can substitute -4 into the equation

`=6/(-2+2*(2.718^(-0.3*-4)))`

`=6/(-2+2*(2.718^(1.2)))`

`=6/(-2+2*2.54)`

`=6/(3.09)`

[tex]=1.94

Therefore f(-4)=1.94

Answer 2

`f(-4)=1.3`

Explanation:

we have

`f(x)=(6)/(-2+2e^(-0.3x))`

we know that

f(-4) is the value of the function for x=-4

substitute x=-4 in the function

`f(-4)=(6)/(-2+2e^(-0.3(-4)))`

`f(-4)=(6)/(-2+2e^(1.2))`

`f(-4)=1.3`