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what is the percentage yield of carbon disulfide if the reaction of 32.0g of sulfur dioxide produces 12.0g of carbon disulfide?

User Herno
by
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1 Answer

4 votes

Answer;

= 63.04 %

Step-by-step explanation;

The balanced equation for the reaction;

5 C + 2 SO2 → CS2 + 4 CO

We can calculate the theoretical yield;

= (32.0 g SO2) / (64 g C/mol) x (1/2) x (76.1418 g CS2/mol)

= 19.035 g CS2 in theory

But;

Percentage yield = Actual yield/theoretical yield × 100%

= (12.0 g) / ( 19.035 g) × 100%

= 0.6304 × 100%

= 63.04%

User Brent Eicher
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6.0k points