Question

potassium chlorate (kclo3) decomposes into potassium chloride (kcl) and oxygen gas (o2) how many grams of oxygen can be produced from the decomposition of 7.38 moles of potassium chlorate​

Answer 1

Consider this reaction : 2KClO3 → 2KCl + 3O2

Mole ratio = 3(O2) : 2(KClO3)

Number of moles of O2 = 3/2*7.38 = 11.07 mol

Number of moles of 02 = mass/molar mass

Therefore, mass = 11.07*(16*2) = 354.24 g

Note: It's mandatory to always balance the reaction at first

Answer 2

`m_(O_2)=354.24gO_2`

Step-by-step explanation:

Hello,

In this case, the undergoing chemical reaction is:

`2KClO_3(s)\rightarrow 2KCl(s)+3O_2(g)`

In such a way, as 7.38 moles of potassium chloride are decomposed, the resulting grams of oxygen are computed considering a 2 to 3 molar relationship in the chemical reaction:

`m_(O_2)=7.38molKClO_3*(3molO_2)/(2molKClO_3)*(32gO_2)/(1molO_2) \\\\m_(O_2)=354.24gO_2`

Best regards.