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Identify the center and the radius of a circle with equation (x-4)^2+(y+2)^2=9

User AlexUA
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2 Answers

1 vote

Answer:

Center at (4,-2); radius: 3

Explanation:

User Hazmat
by
7.5k points
2 votes

Answer:

center:(4,-2)

Radius: 3 units

Explanation:

The standard equation of a circle is given as
(x-h)^2+(y-k)^2=r^2, where (h,k) is the center and r is the radius of the circle.

The given equation is
(x-4)^2+(y+2)^2=9.

We compare to the standard equation of the circle to get;


x-h=x-4


\Rightarrow -h=-4


\Rightarrow h=4

and


y-k=y+2


\Rightarrow -k=2


\Rightarrow k=-2

Hence the center of the circle is (4,-2).

Also, we have
r^2=9

Therefore
r=√(9)


r=3 units.

User Natbusa
by
8.3k points

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