Question

1. How much heat is produced if you heat .25 kg water from 25 degrees C to 100 degrees C. The specific heat of water is 4180 J/kg C.

Answer 1

Q = 78375 [J]

Step-by-step explanation:

To solve this problem we must use the following ideal equation for the thermal energy of an element or substance depending on the temperature change.

`Q=m*C_(p)*(T_(final)-T_(initial))`

where:

Q = heat [J]

m = mass = 0.25 [kg]

Cp = specific heat = 4180 [J/kg*C]

Tinitial = 25[°C]

Tfinal = 100 [°C]

`Q =0.25*4180*(100-25)\\Q = 78375 [J]`