Question

A 13.4-mH inductor carries a current i =
`I_(max)` sin ωt, with
`I_(max)` = 4.80 A and f = ω/2π = 60.0Hz. What is the self-induced emf as a function of time? (Express your answer in terms of t where e m f is in volts and t is in seconds. Do not include units in your expression.)

Answer 1

The voltage across an inductor ' L ' is

V = L · dI/dt .

I(t) = I(max) sin(ωt)

dI/dt = I(max) ω cos(ωt)

V = L · ω · I(max) cos(ωt)

L = 1.34 x 10⁻² H

ω = 2π · 60 = 377 /sec

I(max) = 4.80 A

V = L · ω · I(max) cos(ωt)

V = (1.34 x 10⁻² H) · (377 / sec) · (4.8 A) · cos(377 t)

V = 24.25 cos(377 t)

V is an AC voltage with peak value of 24.25 volts and frequency = 60 Hz.