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H20(l) > h20(g) calculate H rxn

User SupaCoco
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H20 (liquid)- H20(gas)

The Enthalpy change for the above process can be written as:

ΔH=ΔHgas−ΔHliquid

and let us assume the claim in the question is right i.e

ΔHgas>ΔHliquid

User Nilay Mehta
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