Question

Solve the system algebraically. Check your work. 5x + 2y = 10 3x + 2y = 6 ANSWER: {( a0)}

I need a 100% right answer
14 pts.

Answer 1

`x=2`,
`y=0`, or as an ordered pair
`(x,y)=(2,0)`.

Explanation:

We have the system of equations

`5x + 2y = 10` equation (1)

`3x + 2y = 6` equation (2)

Since both equations have the term
`2y`, we are using the elimination method:

Step 1. Multiply equation (2) by -1 and add the result equation to equation (1):

`\left \{ {{-1(3x + 2y = 6)} \atop +{5x + 2y = 10}} \right.`

`\left \{ {{-3x -2y = -6)} \atop +{5x + 2y = 10}} \right.`

Now we can get rid of
`-2y`

`2x=4`

`x=(4)/(2)`

`x=2`

Step 2. Replace the value
`x=2` in equation (1) to find the value of
`y`:

`5x + 2y = 10`

`5(2) + 2y = 10`

`10 + 2y = 10`

`2y = 0`

`y = 0`

We can conclude that the solution of the system of equations is
`x=2`,
`y=0`, or as an ordered pair
`(x,y)=(2,0)`.