Question

What is the final chemical equation from the following intermediate chemical equations?

Answer 1

the answer to that question is a

Answer 2

Answer : The correct option is, (1)
`P_4O_6(s)+2O_2(g)\rightarrow P_4O_(10)(s)`

Explanation :

The two intermediate chemical equations are :

`P_4O_6(s)\rightarrow P_4(s)+3O_2(g)` ..............(1)

`P_4(s)+5O_2(g)\rightarrow P_4O_(10)(s)` .............(2)

Now adding equation (1) and equation (2), we get

`P_4O_6(s)+P_4(s)+5O_2(g)\rightarrow P_4(s)+3O_2(g)+P_4O_(10)(s)`

Now we will cancel the
`P_4(s)` from both the sides of the equation, we get

`P_4O_6(s)+5O_2(g)\rightarrow 3O_2(g)+P_4O_(10)(s)`

Now we will subtracting
`3O_2(g)` from the
`5O_2(g)`, we get

`P_4O_6(s)+2O_2(g)\rightarrow P_4O_(10)(s)`

This is the final chemical equation.