110k views
1 vote
Help me with this one please

Help me with this one please-example-1

2 Answers

5 votes

Answer:

Sin F = 0.7534

Cos F = 0.6575

Tan F= 1.145

Explanation:

From the given figure we can see that,

triangle DEF is right angled triangle

Base = DF = 48

Hypotenuse = EF = 73

Height = ED

To find ED

We have ,

Hypotenuse² = Base² + Height²

EF² = DF² + ED²

ED² = EF² - DF² = 73² - 482

ED² = 3025

ED = √3025 = 55

To find Sin (F)

Sin ∅ =Opposite side /Hypotenuse

Sin F = ED/EF = 55/73 = 0.7534

To find Sin (F)

Cos ∅ =Adjacent side /Hypotenuse

Cos F =DF/EF = 48/73 = 0.6575

To find Sin (F)

Tan ∅ =Opposite side /Adjacent side

Tan F = ED/DF = 55/48 = 1.145

User John Blackberry
by
8.6k points
5 votes

Hello!

The answer is:


sin(F)=(OppositeSide)/(Hypotenuse)=(55)/(73)=0.75


cos(F)=(AdjacentSide)/(Hypotenuse)=(48)/(73)=0.66\\\\tan(F)=(OppositeSide)/(AdjacentSide)=(55)/(48)=1.15

Why?

Since we are working with a right triangle, we can use the Pythagorean Theorem to know the missing side size (Opposite Side).

Pythagorean Theorem formula:


c^(2)=a^(2) +b^(2)

Where:


c=hypotenuse=73\\a=AdjacentSide=48\\b=OppositeSide

So, the opposite side will be:


OppositeSide=\sqrt{c^(2)-a^(2)}=\sqrt{73^(2)-48^(2)}=√(5329-2304) \\OppositeSide=√(3025)=55

Then:


sin(F)=(OppositeSide)/(Hypotenuse)=(55)/(73)=0.75


cos(F)=(AdjacentSide)/(Hypotenuse)=(48)/(73)=0.66\\\\tan(F)=(OppositeSide)/(AdjacentSide)=(55)/(48)=1.15

Have a nice day!

User BobSilverberg
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories