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1 vote
Help me with this one please

Help me with this one please-example-1

2 Answers

5 votes

Answer:

Sin F = 0.7534

Cos F = 0.6575

Tan F= 1.145

Explanation:

From the given figure we can see that,

triangle DEF is right angled triangle

Base = DF = 48

Hypotenuse = EF = 73

Height = ED

To find ED

We have ,

Hypotenuse² = Base² + Height²

EF² = DF² + ED²

ED² = EF² - DF² = 73² - 482

ED² = 3025

ED = √3025 = 55

To find Sin (F)

Sin ∅ =Opposite side /Hypotenuse

Sin F = ED/EF = 55/73 = 0.7534

To find Sin (F)

Cos ∅ =Adjacent side /Hypotenuse

Cos F =DF/EF = 48/73 = 0.6575

To find Sin (F)

Tan ∅ =Opposite side /Adjacent side

Tan F = ED/DF = 55/48 = 1.145

User John Blackberry
by
6.9k points
5 votes

Hello!

The answer is:


sin(F)=(OppositeSide)/(Hypotenuse)=(55)/(73)=0.75


cos(F)=(AdjacentSide)/(Hypotenuse)=(48)/(73)=0.66\\\\tan(F)=(OppositeSide)/(AdjacentSide)=(55)/(48)=1.15

Why?

Since we are working with a right triangle, we can use the Pythagorean Theorem to know the missing side size (Opposite Side).

Pythagorean Theorem formula:


c^(2)=a^(2) +b^(2)

Where:


c=hypotenuse=73\\a=AdjacentSide=48\\b=OppositeSide

So, the opposite side will be:


OppositeSide=\sqrt{c^(2)-a^(2)}=\sqrt{73^(2)-48^(2)}=√(5329-2304) \\OppositeSide=√(3025)=55

Then:


sin(F)=(OppositeSide)/(Hypotenuse)=(55)/(73)=0.75


cos(F)=(AdjacentSide)/(Hypotenuse)=(48)/(73)=0.66\\\\tan(F)=(OppositeSide)/(AdjacentSide)=(55)/(48)=1.15

Have a nice day!

User BobSilverberg
by
7.1k points
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