Question

What are the factors of the square root of 329

Answer 1

x = -3/4 and 7/2 will be your final answer, but check below for a correction on your work

Explanation:

***Your work is incorrect, it should be

2x² - 11x - 21 = 0

you need to subtract an 'x' from both sides, and add 5 to both sides...you added an x to the left side and subtracted a 5 from the left side instead***

I'll solve this so in case you will need help on it too.

Now you'll have

x = (11 ± √[(-11²) - 4(2)(-21)])/([4(2)]

x = (11 ± √289)/8

x = (11 ± 17)/8

x = (11 + 17)/8 = 28/8 = 7/2

or

x = (11 - 17)/8 = -6/8 = -3/4

Answer 2

Answer:
`x=-(3)/(2), 7`

Step-by-step explanation:

`2x^2-10x-26=x-5`

`2x^2-10x-26-x+5=0` Move all terms to one side

`2x^2-11x-21=0` Simplify
`2{x}^(2)-10x-26-x+5`

`2x^2+3x-14x-21=0` Split the second term

`x(2x+3)-7(2x+3)=0` Factor out common terms in the first two terms, then in the last two terms.

`(2x+3)(x-7)=0` Factor out the common term
`2x+3`

`x=-(3)/(2), 7`