B) OA + OB +AB> <BAC
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Applying premise I, OA = OB and OA = OC.
Applying premise II, to ΔOAB, m∠OAB = m∠ABO = m∠ABC.
Applying premise III, to ΔOAC, m∠OAC = ∠ACO = m∠ACB.
Now on application of premise III, it follows that:
2 m∠ABC + 2 m∠ACB = 180° ⇒ m∠ABC + m∠ACB = 90°
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