Question

If water with a mass of 0.755 absorbs 0.954J of heat, how much will its temperature increase?

A. 0.221
B. 0.302
C. 0.095
C. 0.564

Answer 1

Answer: Option (B) is the correct answer.

Step-by-step explanation:

The given data is as follows.

mass = 0.755 g, Q = 0.954 J

`\Delta T` = ? , Specific heat of water, C =
`4.18 J/g^(o)C`

As the relation between heat energy, mass and change in temperature are as follows.

Q =
`mC \Delta T`

0.954 J =
`0.755 g * 4.18 J/g^(o)C * \Delta T`

`\Delta T = 0.302^(o)C`

Thus, we can conclude that increase in temperature is
`0.302^(o)C`.

Answer 2

B. 0.302.

Step-by-step explanation:

• To solve this problem, we can use the relation:

Q = m.c.ΔT,

where, Q is the amount of heat absorbed by water (Q = 0.954 J).

m is the mass of water (m = 0.755 g).

c is the specific heat capacity of water (c = 4.186 J/g.°C).

ΔT is the temperature difference (final T - initial T) (ΔT = ??? °C).

∴ ΔT = Q/m.c = (0.954 J)/(0.755 g)(4.186 J/g.°C) = 3.018 °C ≅ 3.02 °C.