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What is the KE of a 13kg boulder moving at 78.3m/s?
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What is the KE of a 13kg boulder moving at 78.3m/s?

User Salandur
by
5.4k points

2 Answers

11 votes

Answer:

KE =


(1)/(2) m {v}^(2) \\

Step-by-step explanation:


ke = (1)/(2) m {v}^(2) \\ = (1)/(2) * 13 * {78 . 3}^(2) \\ ke = 39850.785j \\

User Vinoth A
by
4.6k points
3 votes

Answer:

39850.785 J

Step-by-step explanation:

0.5 x m x v^2

0.5x13x78.3^2

User Lliane
by
4.3k points
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