What is the KE of a 13kg boulder moving at 78.3m/s?

QAmmunity.org

My account
Edit my Profile
Private messages
My favorites

Ask a Question
Questions
Unanswered
Tags
Categories
Ask a Question

asked Aug 10, 2022 30.3k views

5 votes

What is the KE of a 13kg boulder moving at 78.3m/s?

Physics
high-school

Salandur asked

by Salandur

7.4k points

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

2 Answers

11 votes

Answer:

KE =

$(1)/(2) m {v}^(2) \\$

Step-by-step explanation:

$ke = (1)/(2) m {v}^(2) \\ = (1)/(2) * 13 * {78 . 3}^(2) \\ ke = 39850.785j \\$

Vinoth A answered Aug 11, 2022

by Vinoth A

6.4k points

0 Comments

Please log in or register to add a comment.

3 votes

Answer:

39850.785 J

Step-by-step explanation:

0.5 x m x v^2

0.5x13x78.3^2

Lliane answered Aug 14, 2022

by Lliane

6.1k points

0 Comments

Please log in or register to add a comment.

Ask a Question

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

7.2m questions

9.5m answers

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

2 Answers

0 Comments

Please log in or register to add a comment.

0 Comments

Please log in or register to add a comment.

Other Questions