What is the KE of a 13kg boulder moving at 78.3m/s?

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asked Aug 10, 2022 30.3k views

5 votes

What is the KE of a 13kg boulder moving at 78.3m/s?

Physics
high-school

Salandur asked

by Salandur

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2 Answers

11 votes

Answer:

KE =

$(1)/(2) m {v}^(2) \\$

Step-by-step explanation:

$ke = (1)/(2) m {v}^(2) \\ = (1)/(2) * 13 * {78 . 3}^(2) \\ ke = 39850.785j \\$

Vinoth A answered Aug 11, 2022

by Vinoth A

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3 votes

Answer:

39850.785 J

Step-by-step explanation:

0.5 x m x v^2

0.5x13x78.3^2

Lliane answered Aug 14, 2022

by Lliane

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