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5 votes
Determine the graph of the equation.

(x+3)^2/16 + (y-6)^2/4 = 1

(Picture Provided Below)

Determine the graph of the equation. (x+3)^2/16 + (y-6)^2/4 = 1 (Picture Provided-example-1
Determine the graph of the equation. (x+3)^2/16 + (y-6)^2/4 = 1 (Picture Provided-example-1
Determine the graph of the equation. (x+3)^2/16 + (y-6)^2/4 = 1 (Picture Provided-example-2
User Thokchom
by
6.0k points

2 Answers

6 votes

Answer:

B

Explanation:

edge

User Douglas Correa
by
7.2k points
0 votes

Answer:

Choice B

Explanation:

This is the standard equation of an ellipse centered at (-3,6). Moreover, this ellipse is horizontal since the denominator on the x variable is greater than that on the y-variable. Confirm with the attachment below;

Determine the graph of the equation. (x+3)^2/16 + (y-6)^2/4 = 1 (Picture Provided-example-1
User Massiel
by
6.8k points
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