180k views
2 votes
A square is constructed on side AD of quadrilateral ABCD such that FA lies on AB, as shown in the figure.

If AD : AB = 2 : 5, the coordinates of point F are (?). Point E has the coordinates (2.8, -3), and the coordinates of point D are (?).

F options- (4.4,-4.6) , (4.4,-3.6) , (4.6,-4.6) , (4.6,-3.6)

D options- (4.4,-2.4) , (4.4,-1.4) , (4.6,-2.4) , (4.6,-1.4)


bruh please im struggling

A square is constructed on side AD of quadrilateral ABCD such that FA lies on AB, as-example-1
User Johnsy
by
8.1k points

2 Answers

7 votes

Answer:

F is (4.4, -4.6) and D is (4.4, -1.4).

Hope this helps :)

Explanation:

User Sjkp
by
8.1k points
7 votes

Answer: The co-ordinates of F are (4.4, -4.6) and the co-ordinates of D are (4.4, -1.4).

Step-by-step explanation: Given that a square is constructed on side AD of quadrilateral ABCD such that FA lies on AB as shown in the figure. The co-ordinates of A are (6, -3) and the co-ordinates of B are (10, 1).

Also, AD : AB = 2 : 5 and the co-ordinates of the point E are (2.8, -3).

We are to select the correct co-ordinates of the points F and D.

Let, (a, b) are the co-ordinates of F and (c, d) are the co-ordinates of D.

Since ADEF is a square, so we have

AD = DE = EF = FA.

Given that

AD : AB = 2 : 5, so FA : AB = 2 : 5.

That is, \left(\dfrac{c+4.4}{2},\dfrac{d-4.6}{2}\right)=\left(\dfrac{2.8+6}{2},\dfrac{-3-3}{2}\right)

We have, after applying the internal division formula that


\left((2* 10+5* a)/(2+5),(2* 1+5* b)/(2+5)\right)=(6,-3)\\\\\\\Rightarrow \left((20+5a)/(7),(2+5b)/(7)\right)=(6,-3)\\\\\\\Rightarrow (20+5a)/(7)=6,~~~~~(2+5b)/(7)=-3\\\\\\\Rightarrow 20+5a=42,~~~~\Rightarrow 2+5b=-21\\\\\\\Rightarrow 5a=22,~~~~~~~~~~\Rightarrow 5b=-23\\\\\\\Rightarrow a=4.4,~~~~~~~~~~~\Rightarrow b=-4.6.

So, the co-ordinates of F are (4.4, -4.6).

Now, since ADEF is a square, and the diagonals of a square bisect each other.

So, the mid-points of both the diagonals are same.

That is,


\textup{mid-point of DF}=\textup{mid-point of AE}\\\\\\\Rightarrow \left((c+4.4)/(2),(d-4.6)/(2)\right)=\left((2.8+6)/(2),(-3-3)/(2)\right)\\\\\\\Rightarrow \left((c+4.4)/(2),(d-4.6)/(2)\right)=\left((8.8)/(2),(-6)/(2)\right)\\\\\\\Rightarrow (c+4.4)/(2)=(8.8)/(2),~~~~~~(d-4.6)/(2)=-(6)/(2)\\\\\\\Rightarrow c+4.4=8.8,~~~~~\Rightarrow d-4.6=-6\\\\\Rightarrow c=4.4,~~~~~~~~~~~~\Rightarrow d=-1.4.

So, the co-ordinates of D are (4.4, -1.4).

Thus, the co-ordinates of F are (4.4, -4.6) and the co-ordinates of D are (4.4, -1.4).

User MaTriXy
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories