232k views
0 votes
What is the result of isolating x^2 in the equation below (x+1)^2+(y-8)^2=9

User Felixyz
by
8.0k points

2 Answers

1 vote

Answer:

x² = 8 - (y - 8)² - 2x

x² = 16y - y² - 2x - 56

Explanation:

∵ (x + 1)² + (y - 8)² = 9

∵ x² + 2x + 1 = 9 - (y - 8)²

∴ x² = 9 - (y - 8)² - 2x - 1

∴ x² = 8 - (y - 8)² - 2x

OR:

∵ x² = 8 - (y² -16y + 64) - 2x

∴ x² = 8 - y² + 16y - 64 - 2x

∴ x² = 16y - y² - 2x - 56

User Itwasntme
by
8.7k points
3 votes

Answer:

x² = 16y-y²-2x-56

Explanation:

We have given the equation:

(x+1)²+(y-8)²=9

We have to solve it for x².

So, the above equation is:

(x+1)²+(y-8)²=9

Open the square of the terms we get,

x²+1+2x+y²+64-16y = 9

x²+2x+y²-16y+65 = 9

The equation in terms of x² is:

x²= 9-2x-y²+16y-65

x² = 16y-y²-2x-56 is the answer.

User Martinyyyy
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories