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Factor completely:
6u^2·(2u−5)^2−12u^2·(2u−5)·(u+5)

2 Answers

4 votes

Assignment:
\bold{Factor \ Equation: \ 6u^2\left(2u-5\right)^2-12u^2\left(2u-5\right)\left(u+5\right)}

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Answer:
\boxed{\bold{-90u^2\left(2u-5\right)}}

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Explanation:
\downarrow\downarrow\downarrow

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[ Step One ] Factor Out Common Term
\bold{6u^2\left(2u-5\right)}


\bold{6u^2\left(2u-5\right)\left(2u-5-2\left(u+5\right)\right)}

[ Step Two ]
\bold{2u-5-2\left(u+5\right)}


\bold{-15}

[ Step Three ] Rewrite Equation


\bold{-15\cdot \:6u^2\left(2u-5\right)}

[ Step Four ] Refine


\bold{-90u^2\left(2u-5\right)}

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\bold{\rightarrow Mordancy \leftarrow}

User Erwin Zhang
by
5.3k points
2 votes

6u²*(2u-5)²-12u²*(2u-5)*(u+5)

-90u²*(2u-5)

User Forgottofly
by
4.6k points
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