Question

Point A has coordinates (-5,-3). What are the coordinates of the image if point A is translated five units down?

(0,-3)
(-5,2)
(-10,-3)
(-5,-8)

A(5, 3), B(2, 1), and C(-2, 4) are the coordinates of a triangle's vertices. If the triangle is translated right 5 units, what are the coordinates of the image?

A'(5, 8), B'(2, 6), C'(-2, 9)
A'(0, 3), B'(-3, 1), C'(-7, 4)
A'(10, 8), B'(7, 6), C'(3, 9)
A'(10, 3), B'(7, 1), C'(3, 4)

PLZ HELP ASAP PLZ I have to turn this in now

Answer 1

(5, -3)

Explanation:

Answer 2

Ques 1)

The coordinates of the image if point A is translated five units down is:

(-5,-8)

Ques 2)

The coordinates of the image are:

A'(10, 3), B'(7, 1), C'(3, 4)

Explanation:

Ques 1)

We know that if a point which is located at (x,y) is translated some k units down that the rule for the transformation that holds is given by:

(x,y) → (x,y-k)

Here we have: A(x,y)=(-5,-3)

and k= 5

Hence, the location of the translated point is given by:

(-5,-3) → (-5,-3-5)

i.e. (-5,-3) → (-5,-8)

Hence, the answer is: (-5,-8)

Ques 2)

We know that if any points is located at (x,y) and it is translated some k units to the right then the rule for the transformation is given by:

(x,y) → (x+k,y)

Here we have: k=5

Hence, we get:

A( 5,3) → A'(5+5,3) i.e. A(5,3) → A'(10,3)

B(2,1) → B'(2+5,1) i.e. B(2,1) → B'(7,1)

C(-2,4) → C'(-2+5,4) i.e. C(-2,4) → C'(3,4)