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Multiply (2x-5)(3x^2-4x+2)
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Multiply (2x-5)(3x^2-4x+2)

User Abbottmw
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1 Answer

2 votes

Answer:


\large\boxed{(2x-5)(3x^2-4x+2)=6x^3-23x^2+24x-10}

Explanation:


\text{Use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(2x-5)(3x^2-4x+2)\\\\=(2x)(3x^2)+(2x)(-4x)+(2x)(2)+(-5)(3x^2)+(-5)(-4x)+(-5)(2)\\\\=6x^3-8x^2+4x-15x^2+20x-10\\\\\text{combine like terms}\\\\=6x^3+(-8x^2-15x^2)+(4x+20x)-10\\\\=6x^3-23x^2+24x-10

User Tim Kist
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