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Is x^2 + 1/x = 4 a quadratic equations​

User Liuhongbo
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1 Answer

13 votes

Answer:


\large\boxed{\pink{ \leadsto The \ given \ equation \ is \ not \ a \ Quadratic \ equation . }}

Explanation:

Given equation to us is ,


\green{\implies x^2+(1)/(x)=4 }

So , a equation is said to be a quadratic equation if the highest degree of the variable is 2 . On simplifying the Equation ,


\implies x^2 +(1)/(x)=4

Taking x as LCM ,


\implies (x^2.x + 1 )/(x)= 4

Transposing x to RHS .


\implies x^3 + 1 = 4x

Putting all terms in LHS


\boxed{\bf \implies x^3 - 4x - 1 = 0 }

Since here the highest degree of the variable is 3 not 2 . So its a cubic equation and not a quadratic equation .

Hence the given equation is not a quadratic equation .

User Derflo
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