Question

A circle with center c(4,-2) contains the point D( 8,1). What is the equation of the line perpendicular to the radius of the circle passing throug the point C

Answer 1

4x +3y = 10

Explanation:

The radius CD has slope Δy/Δx = (1-(-2))/(8-4) = 3/4.

The equation for the perpendicular line through point C(4, -2) can be written as ...

Δx(x -4) +Δy(y -(-2)) = 0

4(x -4) +3(y +2) = 0

4x +3y -10 = 0 . . . . . . general form equation for the line

4x +3y = 10 . . . . . . . . .standard form equation for the line